A lab technician is preparing agar medium. The medium requires 21 grams (g) of agar, 500 mg of dextrose, 3 dg of sodium, and 1 cg of potassium per 1,000 milliliters
(mL) of distilled water.
What is the total weight in g of the dry ingredients?

21.81grams

Explanation:

According to the question, an agar medium requires the following ingredients: 21 grams (g) of

agar, 500 mg of dextrose, 3 dg of sodium, and 1 cg of potassium per 1,000 milliliters (mL) of distilled water.

Hence, the dry ingredient contain 21grams (g) of agar, 500milligrams (mg) of dextrose, 3decigrams (dg) of Sodium, and 1centigrams (cg) of pottasium.

We need to convert all units (not in grams (g)) to grams.

1grams = 1000milligrams

500 milligrams = 500/1000

= 0.500grams.

1grams = 10decigrams

3decigrams = 3/10

= 0.3grams

1grams = 100centigrams

1centigrams = 1/100

= 0.01 grams

Therefore, we have 21g, 0.500g, 0.3g, and 0.01g

The total dry weight of the ingredients will be:

21 + 0.500 + 0.3 + 0.01

= 21.81grams

132

explanation:

12

the bald eagle got 50 because everything gets 10% of what they consume and since 50 is ten % of 500 hundred that means the   grasshopper had to have consumed a plant with 5,000 calories of energy