Two true-breeding stocks of garden peas are crossed. One parent had green, inflated pea pods and the other had yellow, constricted pea pods, ; all the F1 individuals had green, inflated pea pods. If 1400 F2 offspring resulted from the cross, approximately how many of them would you expect to have green, constricted pea pods

The correct answer is : 262.5

Explanation:

Given:

F1 plants - green, inflated pea pods.

Parents = pure breed.

So, the green and inflated pods are dominant

solution:

Let G = green color and dominant over g =  yellow color.

Similarly, I = inflated which is dominant over i constricted pod.

Parents: GGII × ggii

F1: GgIi ( green, inflated)

Parents: GgIi × GgIi

Punnet square:  find attachment

The green constricted seeds are found in the proportion of 3/16

The number of green and constricted seeds out of 1400

=(3/16)×1400

=262.5

Thus, the correct answer is : 262.5

i'm guessing this is from edg enuity so the answers would be, from top to bottom,

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