g In the opium poppy, leaves can either be normal-shaped or lacerate (with rough edges). Leaf shape is determined by two loci, A and B. A single dominant allele at either gene (i. e. either A/- OR B/-) is sufficient to get normal-shaped leaves. A pure breeding plant with normal leaves was crossed with a pure breeding plant with lacerate leaves to generate an F1. If this F1 is selfed, what will be the ratios of normal:lacerate leaved plants in the F2 generation

15:1

Explanation:

Normal shape leaf is controlled by A/_ or B/_.

Pure breeding normal leaf shape plant would have the genotype AABB.

A pure breeding lacerate leaf plant would have the genotype aabb.

              AABB    x    aabb

                         AaBb

At F1, all the offspring would have normal shape leaves. If F1 is selfed:

        AaBb    x    AaBb

A_B_  Normal leaved plants = 15/16

aabb Lacerate leaved plants =  1/16 (See the attached image for the Punnet's square)

Hence, the ratio of normal:lacerate leaved plants at F2 would be 15:1

the bullets go in this order.

4, 1, 3, 5, 2

answer:   option a) glucagon was secreted by his pancreas before he ate the cookies because blood glucose was low. insulin was secreted after he ate the cookies because his blood glucose was high.

explanation: