Carbon-14 has a half-life of 5,730 years. Suppose a fossil from a mammal contains one-fourth of its original amount of carbon-14. How old is the sample?

a:22,920 years
b:17,190 years
C:2,865 years
d:11,460 years

 B:17,190 years

Explanation: After 5730 years ( first half life) 70 /2 = 35 mg decays and 35 g remains left. After another 5730 years ( two half lives or 11460 years) 35 /2 = 17.5mg decays and 17.5 g remains left . After another 5730 years ( three half lives or 17190 years) 17.5 /2 = 8.75mg decays and 8.75g remains left.

i know this is off topic but, can you go to my quetions, to see if you can answer any?(or if you know anyone who can answer them)

d

explanation:

the higher the instrument the better

the awnser is d i think