Identify events that contribute to the termination of a response in the GPCR, or 7TM receptor, pathway. Select all that apply.

Multiple choices:

1. G? dissociates from the G?? subunits.

2. The ligand dissociates from the receptor, which resumes its inactive conformation.

3. The receptor is inactivated by phosphorylation of Ser or other residues on its intracellular domain.

4. G? releases GDP and binds GTP.

5. G? hydrolyzes GTP to GDP and Pi.

Answers

The ligand dissociates from the receptor, which resumes its inactive conformation

The receptor is inactivated by phosphorylation of Ser or other residues on its intracellular domain

G? hydrolyzes GTP to GDP and Pi

Explanation:

The GPCRs known in full as G protein-coupled receptors are viewed by many as the largest group of membrane proteins that are found in human genome. They share a common architecture. The seven-transmembrane (7TM) receptors are mostly used interchangeably with the GPCRs even though there are known receptors that have seven membrane domains and do not just signal through the G proteins.

it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.

then go eat. lol.brainliest