1. if a cell has a large surface area to volume ratio, it
exchanges materials will its environment efficiently.
exchanges materials will its environment inefficiently.
needs to divide to increase efficiency.
is too large to survive.
2. compared to small cells, large cells have more trouble
dividing.
producing daughter cells.
storing needed materials and waste products.
moving needed materials in and waste products out.
3. bacteria cells reproduce by which process?
mitosis
meiosis
binary fission
sexual reproduction
4. an advantage of sexual reproduction over asexual reproduction is that sexual reproduction
takes less time.
requires more time.
provides genetic diversity.
produces identical offspring.
5. which of the following describes a type of cell division that produces cells used in sexual reproduction?
mitosis
meiosis
binary fission
cell splitting

The correct answer of Q 1 is- exchanges materials with its environment efficiently.  

If a cell has a large surface area to volume ratio than materials can easily move in and out of the cell due to the small size of the cell. As the surface area to volume ratio decreases materials from the surrounding environment move slowly inside the cell.

The correct answer of Q 2 is- moving needed materials in and waste products out.

Large cell requires more nutrients and produce more waste material than smaller cell and their movement is more difficult in larger cell, therefore, cell reduce size by dividing.

The correct answer of Q 3 is- binary fission

Bacterial cells divide by binary fission into two equal half which is a type of asexual reproduction.

The correct answer of Q 4 is- provides genetic diversity

As sexual reproduction require the fusion of gametes from two different individuals it provides genetic diversity in the population.  

The correct answer of Q 5 is-meiosis

Meiosis is the type of cell division which helps to reduce the chromosome number by half in sex cell or gametes because in sexual reproduction half of the chromosome comes from one individual and half from another.

it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.