Assume that plant height is determined by a pair of alleles at each of two loci (A and a, B and b) that are additive in their effects. Further assume that each allele represented by an uppercase letter contributes 6 feet to height and that each allele represented by a lowercase letter contributes 2 foot to height. If a plant with genotype AaBB is crossed to a plant with genotype aaBb, what heights are expected in the progeny

16 feet, 20 feet, and 12 feet

Explanation:

Uppercase allele = 6 feet

Lowercase allele = 2 feet

First, let us look at the outcome of the cross between AaBB and aaBb.

      AaBB     x     aaBb

Progeny:

4 AaBB = 6+2+6+6 = 20 feet

4 aaBB = 2+2+6+6 = 16 feet

4 AaBb = 6+2+6+2 = 16 feet

4 aaBb = 2+2+6+2 = 12 feet

The heights expected in the progeny are 16 feet, 20 feet, and 12 feet.

answer: the answer is b

the level of progesterone is low at the pre-ovulatory phase of the cycle but it gradually increases and the levels are high at the luteal phase. if pregnancy occurs, the level of progesterone will be high throughout the pregnancy.

if egg is fertilized and the mother gets pregnant, progesterone starts preparing the uterus for the implantation. it starts building up the lining of uterus and make it hostile of the period of pregnancy.