Mendel performed dihybrid crosses in which the P generation had more than one characteristic that differed. If a dihybrid cross is made in which the parents were YYTT and yytt, what is the probability that the offsping will show the dominant phenotype for both traits? Hint: You don't need to use a Punnett Square to solve this.

1. 0%
2. 25%
3. 50%
4. 75%
5. 100%

The correct answer is -Option 5. 100%

Explanation:

In this dihybrid cross, Parents are crossed that are a true breed which means they either have dominant alleles or recessive for all the traits. Parent one is having dominant alleles YYTT and parent 2 is having alleles recessive for the trait yytt.

They both parents form gametes that are YT and yt which leads to heterozygous offspring for the traits as there is a single copy of each allele for each trait.

Thus, the offspring will have YyTt genotype in all offspring which express the dominant phenotype.

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