Biology, 03.11.2020 16:50 unknown337

Not all restriction enzymes necessarily cleave DNA at rotationally symmetric sites. For example, the recognition site of the restriction enzyme Bst XI is 5' CCA^NTGG, where the symbol ^ represents the cleavage site and N means any nucleotide. Make the simplifying assumptions that equal amouts of all four nucleotides exist in the human genome, and that its base sequence is random. How frequently would you expect to find Bst XI recognition sites in the human genome

Answers: 3

Show answers

Answers

Answer from: shay8850

The frequency of Bst XI recognition sites in the human genome is once every 65536 bases in the human genome.

The frequency of cutting in a random DNA sequence for a given restriction enzyme, F = once per every 4^n nucleotide bases.

where n is the number of bases in the restriction enzymes recognition sequence. The number 4 is obtained from the fact that there are four different possible nucleotides that may be inserted at any one position (G, A, T, or C).

Given the recognition site of the restriction enzyme Bst XI as 5' CCA^NTGG,

where the symbol ^ represents the cleavage site and N means any nucleotide.

Therefore, the number of nucleotide bases, n in the recognition sequence of Bst XI is eight nucleotide bases i.e. CCA

Assuming that equal amounts of all four nucleotides exist in the human genome, and that its base sequence is random:

Using the formula, frequency = 4^n

for Bst XI, n = 8

Frequency = once per 4⁸ nucleotide bases

Frequency = once per 65536 nucleotide bases

Therefore, the frequency of Bst XI recognition sites in the human genome is once every 65536 bases in the human genome.

Learn more about restriction enzymes at: link

Answer from: kailinaguilar2187

The frequency to be expected in order to find Bst XI identification sites in the human genome would be:

- Bst XI will cleave the DNA on average once in 4096 base pairs: one out of 4096 DNA fragments will have compatible ends.

In the question, the sequence of the Bst XI is given:5' CCA'NTGG 3', here 'sign is the site of restriction. It is also given that N = any nucleotide and equal amounts of nucleotide present in the human genome.Probability of anyone nucleotide = 1/4 (G = A = T = C = 1/4 )Nucleotide is equal so we can neglect it as its probability is:

1. Number of bases = 6so, the probability of occurrence of the site with 6 different bases = (1/4)^6= 1/4096

Thus, It means the enzyme Bst XI will cut DNA at once in every 4096 bases.

Learn more about "bases" here:

link

Answer from: Quest

a unit of heredity that is transferred from a parent to offspring and is held to determine some characteristic of the offspring.

Answer from: Quest

The correct answer is b)

Another question on Biology

Biology, 21.06.2019 23:30

What the theory that the sun goes around earth was replaced with the theory that earth goes around the sun this was an exaple of a

Answers: 1

Answer

Biology, 22.06.2019 01:00

Why would a drug the damages capsids treat a viral infection

Answers: 1

Answer

Biology, 22.06.2019 16:30

9. technology can bring both good and bad things. building a vertical farm can increase food supplies in cities (good), but it may cause unemployment in rural areas (bad). give another example of both the good and bad sides of a technological advancement (5 noints)

Answers: 1

Answer

Biology, 22.06.2019 19:40

4. multiple crosses were made between true-breeding lines of black and yellow labrador retrievers. all the f1 progeny were black. when these progeny were intercrossed, they produced an f2 consisting of 91 black, 39 yellow and 30 chocolate. a. propose an explanation for the inheritance of coat color in labradors. b. propose a biochemical pathway for coat color determination and indicate how the relevant genes control coat coloration.

Answers: 2

Answer

You know the right answer?

Not all restriction enzymes necessarily cleave DNA at rotationally symmetric sites. For example, the...

Questions