Write the equation of a line that is parallel to y = 0.62 + 3 and that passes through the point (-3,-5). Answer is y=0.6x-3.2

y = 0.6.x - 3.2

Explanation:

The slope-intercept form:

y = mx + b

m - slope

b - y-intercept

We have

y + 0.6x + 3

Parallel lines have the same slope. Therefore we have the equation:

y + 0.6x + b

The line passes through the point (-3, -5). Put the coordinates of the point to the equation and solve it for b:

-5 = 0.6(-3) + b

-5 = - 1.8 + b

-3.2 = b

           add 1.8 to both sides

Finally we have:

y = 0.6.x - 3.2

{Not mine :(}