An ant and a stone are on a circular disc, which is rotating at a constant speed. The stone is fixed to the disc. The ant is moving along the rim in the opposite direction and at the same speed as that of the disc. Which of these shows the position of the ant and the stone after the disc completes 3/4th of a revolution?

Find attached the options

The option B in the attached is correct

Explanation:

In the given scenario the ant and stone are on the same disc and the stone is fixed.

The disc is moving at a constant speed in a clockwise direction while the ant is moving in the opposite direction.

The starting position is also attached with the ant opposite the stone.

So for a full rotation the ant would have gone round and met up with the stone.

If the disc completes a 3/4th revolution it will be at the position in B. The ant would have gotten to the stone by half revolution, and by 3/4th revolution it would have gone a quarter of the disc from the stone as shown

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it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.