If tanA= x/y find the value of xsinA+ycisB

If tan A = 3 / 5, then sin A = 3√34 / 34 and cos A = 5√34 / 34  .

Assuming x = 5 and y = 3 (The problem is deficient in this regard)

5(3√34 / 34) + 3(5√34 / 34)

30√34 / 34

15√34 / 17

Explanation:

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