Applying the chi-square test of independence to case and control genotypes at five SNPs (labeled SNP01, SNP02, SNP03, SNP04, SNP05), yields the respective p-values 0.05, 0.04, 0.009, 0.004, and 0.10. The genetic phenotype is Fructosia. After Bonferroni correction for multiple testing, what SNPs are declared to be significantly associated with Fructosia at the 5% significance level