The typical male turkey has a mass of 17.5 lbs whereas the typical female turkey has a mass of 8.0 lbs. How many ounces of insects would 7 gobblers consume daily to sustain themselves?

The answer is below

Explanation:

It have been shown that domestic  turkeys require about 13.6 grams of food per pound of body weight each day to sustain weight. A gobbler is a male turkey.

The food consumed by a male turkey that is 17.5 lbs = 13.6 grams of food per pound * 17.5 pound = 238 grams.

7 gobblers = 7 male turkeys, hence:

The food consumed by 7 gobblers = 238 grams * 7 = 1666 grams

the cladogram shown here shows similarities and differences among several classes of vertebrates. anatomically, the four have limb structure as their common ancestor. we might separate the mammals from the other three classes because they a) divergent; do not lay eggs b) identical; are warm-blooded c) varied; a four chambered heart d) homologous; have mammary glands