A woman heterozygous for polydactyly (extra fingers and toes), a dominant trait, is married to a normal man. What is the probability of producing an offspring that has extra fingers or toes?

Polydactyly is a condition that occurs wherein individuals have more than the normal amount of fingers and toes. It is also a genetic condition and as well heritable.

The probability of producing an offspring with extra toes or fingers in a cross between an heterozygous and a normal is 50%.

Let P represent the dominant and p the recessive

Pp (heterozygous) and pp (normal)

 (woman)      P        p

 (man) p     Pp        pp

           p     Pp        pp

                  50%      50%

Therefore, the probability of producing an offspring with extra toes or fingers (Pp) is 50%.

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The correct answer is -50%

Explanation:

Polydactyly is a dominant trait where a person gets an extra finger or toes the dominant allele is represented by P = allele for polydactyly, and the recessive allele represented by p = normal allele

So, the heterozygous woman will be - Pp & the normal man will be - pp.  The presence of one allele of polydactyly will be able to show its effect as it is dominant.

Cross between heterozygous woman & normal man:

Gametes:

   P                              p

p Pp (Show polydactyly)pp (Normal phenotype)

p Pp (Show polydactyly)pp (Normal phenotype)

From the above Punnett square, the probability of an offspring that has extra fingers or toes will be 1/2 or 50%.

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