Two genes control color in corn snakes as follows: O- B- snakes are brown, O- bb are orange, oo B- are black, and oo bb are albino. An orange snake was mated to a black snake, and a large number of F1progeny were obtained, all of which were brown. When the F1 snakes were mated to one another, they produced 100 brown offspring, 25 orange, 22 black, and 13 albino. a. What are the genotypes of the F1 snakes

The correct answer is - OoBb

Explanation:

As it is given that:

O- B- snakes = brown

O- bb = orange

oo B = black

oo bb = albino

And here, the cross between an orange snake and black snake which means:

P0 : ooBB × OObb

offspring of f1 would be =

F1 : OoBb

self cross of f1 offsprings

F2 : OoBb × OoBb

Gametes  OB     Ob        oB           ob

OB OOBB OOBbOoBBOoBb

Ob OOBb OObbOoBbOobb

oBOoBBOoBbooBBooBb

obOoBbOobbooBboobb

here we get approximately similar as Phenotypic ratio as mention in question- 9 : 3 : 3 : 1 or 100:25:22:13

Thus, the correct answer would be: OoBb

both anaerobic and aerobic respiration use glucose (or other carbohydrates), proteins and lipids to produce atp and nadh. cell uses those energy molecules, obtained from food and   breaks them down during the chemical reactions of respiration. in anaerobic respiration, nadh is regenerated to nad+ by enzymes lactate dehydrogenase (lactate is produced, e.g. in muscle cells) or by alcohol dehydrogenase where ethanol is produced (alcohol fermentation), while in aerobic respiration, electrons from nadh are deposited in the mitochondria to regenerate nad+ (electron transport chain. anaerobic respiration produces 2 atp per molecule of glucose compared to aerobic respiration where about 38 atp molecules are produced.