red-green color blindness is an x-linked recessive disorder. if the mother is RGCB and the father has normal vision, what are the changes for daughters and sons to hae the trait

The correct answer would be -

RGCB daughter - 0%

RGCB sons - 100%

Explanation:

Red-green color blindness is a sex-linked recessive disease that means it will only express in absence of the normal allele that is present on X-chromosomes. As it is known that males have only one X-chromosomes therefore, the chances are more in males to be affected in presence of the recessive gene. In this given case women s RGCB and man has normal vision. The genotype of women would be both recessive alleles XcXc and genotype of man would be XY.

The gametes would be - Xc, Xc and X, Y

then the cross:

       Xc     Xc

X     XXc    XXc

Y    XcY      XcY

so the offspring would be -

Carrier female =  XXc (50% chance in total and 100% in daughters)

RGCB daughters = 0%

RGCB male =  XcY (100% in sons and 50% of total children)

really dont know just need some points