An inflated basketball hold 6 liters of air at 3 ATM. How much air at 1 ATM went into the ball

18 litres

Explanation:

Using Boyle's law equation as follows:

P1V1 = P2V2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (litres)

V2 = final volume (litres)

According to the information in this question, An inflated basketball hold 6 liters (V1) of air at 3 atm (P1). The volume of air (V2) at 1 atm (P2) that went into the ball can be calculated thus:

Using P1V1 = P2V2

3 × 6 = 1 × V2

18 = V2

V2 = 18 litres.

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