Part 3: Selection Selection can be for or against a particular phenotype. In this part, you'll look at both. 1. To examine heterozygote advantage (perhaps the variance in pattern makes it more difficult for individuals to be spotted by a predator), return to the original parameters for population size, carrying capacity, and initial 'R' proportion, but decrease the Genotype Relative Fitness of the rr and RR individuals to 0.7 to indicate the advantage experienced by the heterozygote. Click the reset button to begin data collection. Allow the Allele Proportion vs Time 1 simulation to run for at least 100 generations, then sketch the graph: a. Proportion of "R" 0.5 b. Do any of the phenotypes go to zero? Why does this make sense?

the unequal cytoplasmic division that  results  in  one egg  and three polar bodies ensures that a fertilized  egg has  ample nutrients  forits journey  to  the uterus.

events in order:

1.       vishnu schist

2. zoroaster granite

3. bass limestone

4. hakatar   shale

5. igneous intrusion

6. shinumo quartzite

7. dox sandstone

8. tapeats limestone

9. bright angel shale

10. muav limestone

11. temple butte limestone

12. redwall limestone  

nonconformity

answer: the unkar group shows angular unconformity because the layers are turned at angle.

unconformity

answer: specifically the angular unconformity occurs between the cambrian and precambrian rocks. the dox sandstone, shinumo quartzite, hakatar shale, and bass limestone have been filled. an angular unconformity occurs between the cambrian and precambrian rocks. the dox sandstone, shinumo quartzite, hakatar shale, and bass limestone have been filled.

disconformity

answer: the disconformities aremarked irregular lines between the sedimentaryrocks layers.

answer: carbon 14 can only be used to determine the age of the organisms that were once living, and igneous rocks are non living.

explanation: