How many grams of water can be heated from 20.0 oC to 75oC using 12500.0 Joules? The specific heat of water = 4.186 joule/gram °C

The correct answer is - 0.054 kg

Explanation:

Given:

change in temperature: 55°C

Heat energy = 12500 J

specific heat = 4.186

Formula:

The formula for Heat Energy is given by:

Q = mcp∆T

here: Q - Heat Energy

m is for mass

cp is for specific heat

∆T is a change in temperature,

Solution:

From formula,

m = Q/ cΔT

Mass = 12500 / (55 × 4200)

= 0.054 kg or 54 g

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