The allele for a widow’s peak has complete dominance over the allele for a straight hairline (w). what is the probability of two parents heterogeneous for a widow’s peak (ww) having an offspring without a widow’s peak? 25 percent 0 percent 50 percent 75 percent

Option A

Explanation:

It is given that allele for a widow’s peak (W) is completely dominance over the allele for a straight hairline (w).

Two heterogeneous parents are crossed with genotype (Ww)

Therefore following offspring are produced-

Ww * Ww

WW

Ww

Ww

ww

Thus, out of four only one offspring with genotype (ww) will be without a widow’s peak.

Thus, the probability of having an offspring without a widow’s peak

%

Thus, option A is correct

it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.