What is the specific heat of aluminum if the temperature of a 28.4 g sample of aluminum is increased by 8.1oC when 207 J of heat is added? 0.900 Jg℃

0.900 Jg^-1℃^-1

Explanation:

Given that;

H = mcθ

H = heat added

m = mass of aluminium

c = specific heat of aluminum

θ = increase in temperature

Making c the subject of the formula;

c = H/mθ

c = 207 J/28.4 g * 8.1oC

c = 0.900 Jg^-1℃^-1

biology is the study of life. it is the study of living organism.

it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.