Three genes (A, B, and C) are located on different chromosomes. In a cross between AaBCC and AabbCc (P generation) what would be the probability of seeing an
offspring with the genotype AAbbCc in the Fı generation (assuming no linkage)?

b, a, c

Explanation:

Since recombination frequency is directly proportional to the distance between genes, the values are used to locate genes on a chromosome. Here three genes a, b and c can assume any of three linear sequences: a-b-c or a-c-b or b-a-c, which depends on the gene present in the middle. Here, recombination frequency for a and b (X) = 20%, that for a and c (Y) = 8% and for b and c (Z) =28%. As we can see that Z = X + Y or 28 = 20+8 which means that genes b and c are present at extremes and a is in the middle. Thus, the sequence of genes is b-a-c.

answer; the correct answer is conflict- related aggression; +

silty loam

hope this