Use the coordinates of the labeled point to find the point-slope equation of the line
-5
5
-5
(3.-5)
O A. y+ 5 = -3(x - 3)
B. y- 5 = -3(x+3)
C. y + 5 = 3(x+3)
O D. Y-3 - (x+5)

A. y + 5 = -3(x - 3)

Explanation:

Given the following data;

Points on the graph (x1, y1) = (3, -5)

Points on the graph (x2, y2) = (0, 4)

First of all, we would determine the slope of the equation of line;

Mathematically, the slope of a line is given by the formula;

Substituting into the formula, we have;

Slope, m = -3

Next, to find the point-slope equation of the line, we would use the following formula;

y - y1 = m(x - x1)

y - (-5) = -3(x - 3)

y + 5 = -3x + 9

y = -3x + 9 - 5

y = -3x + 4 = mx + c

a

explanation:

many plants naturally reproduce this way, but it can also be induced artificially. horticulturalists have developed asexual propagation techniques that use vegetative plant parts to replicate plants. success rates and difficulty of propagation vary greatly. monocotyledons typically lack a vascular cambium and therefore are harder to propagate.

c is the answer : )               your welcome