What is the probability that a hybrid individual with the genotype AabbCcddEeFf will produce a gamete that has the genotype abCdeF

6.25%

Explanation:

Find the number of different gametes that can be produced

number of gametes produced = 2^n

n is the number of allele pairs that are heterozygous

there are 4 heterozygous allele pairs, these are: Aa, Cc, Ee and Ff

2^4 = 16

abCdeF is one of the 16 genotypes that could be produced

to find the percentage, divide 1 and 16 and multiply by 100

1 ÷ 16 = 0.0625

0.0625 × 100 = 6.25