Suppose that the concentration of Na outside the cell is 100 and inside the cell is 10 mmol/liter. The Nernst equation at 20oC is: You set the membrane voltage at 58 millivolts using a voltage clamp, and measure membrane current. If Na is the only ion crossing the membrane, you would expect to see: Group of answer choices

Complete question:

Suppose that the concentration of Na+ outside the cell is 100 and inside the cell is 10 mmol/liter. The Nernst equation at 20oC is:

Eion = 58 millivolts/z. [Log₁₀ (C-out/C-in)

You set the membrane voltage at +58 millivolts using a voltage clamp, and measure membrane current. If Na+ is the only ion crossing the membrane, you would expect to see:

a) 0 current

b) positive charges flowing into the cell

c) negative charges flowing into the cell

d) the membrane voltage becomes more positive

b) positive charges flowing into the cell

Explanation:

Nernst equation:

E = 58 millivolts/z. [Log₁₀ (C-out/C- in)

Where,

The bigger concentration value places in the numerator and the smaller concentration value laces in the denominator.  

Now let us see the provided values,

E = 58 millivolts/z. [Log₁₀ (Ion out/Ion i)

E = 58 millivolts/+1. [Log₁₀ (100mmol/liter / 10 mmol/liter)

E = 58 millivolts (Log₁₀ 10)

E = 58 millivolts (1)

E = 58 millivolts

58 mV is the absolute value of equilibrium potential.

Due to the differences in concentration, and being the only ion crossing the membrane, Na+ diffuses from outside -which is the highest concentration side- to the interior of the cell -which is the lowest concentration side-. Positive charges are moving into the cell. The interior of the cell becomes more positive.

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