The table shows the solubility of two substances in water at 20°c. mass 100 solubility of sodium chloride l solubility of lead nitrate 54 mass 200 solubility of sodium chloride 36 solubility of lead nitrate k what is the difference between k and l. explain you answer

the correct answer is 36

Explanation:

The two substances are sodium chloride and lead nitrate

In case of sodium chloride;  

mass of water = 100 kg

solubility of sodium chloride = 54 g / 100 g of water

Therefore the mass of sodium chloride required for full saturation,

L = (54/100) x 100 kg = 54 kg

In case of lead nitrate;  

mass of water = 200 kg

mass of lead nitrate = 36 kg

if the solution is fully saturated, solubility of lead nitrate (g per 100 g of water)

k = (36/200) x 100 g   = 18 g  

k can be also written as 18 kg per 100 kg of water.

thus the difference in k and l = (54-18) = 36.

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