In a dihybrid cross with genotypes jjqq and jjqq, what is the probability of getting an offspring with genotype jjqq?  

1/4

Explanation:

A dihybrid cross is a cross between two individuals in which two different traits are analyzed.

In the problem, the genes are J/j and Q/q.

To analyze the genotypes of the offspring, a Punnett Square is needed. See the image attached. If you count them, the genotype JjQq appears 2 out of 8 times, so the probability of getting that genotype in the offspring is 2/8 = 1/4.

each of the 46 original chromosomes splits into two daughter chromosomes, so there are two sets of 46 daughter chromosomes that end up in each cell. human cells have 46 chromosomes. each chromosome consists of a pair of identical chromatids attached together by a structure called a centromere.

he forelimbs below belong to four species that descended in a direct line from the ancestral mammal shown above. of the four descendants shown, which species most likely appeared earliest in evolutionary history?