Suppose 64% of a remote mountain village can taste phenylthiocarbamide (ptc) and must, therefore, have at least one copy of the dominant ptc taster allele. if this population conforms to hardy-weinberg equilibrium for this gene, what percentage of the population must be heterozygous for this trait?

The answer is; 48%

This is how to calculate;

Let's assign the dominant allele letter ‘T’ and the recessive letter ‘t’

Using the hardy weignburg equation; p2 + 2pq + q2  = 1

P2 + 2pq = 0.64

q2 = 1 – 0.64 = 0.36

q = 0.6

Remember that; p + q = 1

P = 1 – 0.6 = 0.4

Now to calculate population with herozygour trait = 2pq

2 * 0.4 * 0.6 = 0.48

This means 48% of the population is heterozygous for the trait that enable tasting of phenylthiocarbamide

try using substitution:

x + y - 6 = x - y. (i'm not giving you the exact answer). since 0 = x - y, then sub 0 in the equation with x - y. combine your like terms, and then use inverse operations, and you'll have your answer.

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