Some people have the ability to taste a bitter chemical called phenylthiocarbamide (ptc). the ability to taste ptc is due to the presence of at least one dominant allele for the ptc taste gene. the incidence of nontasters in north america is approximately 45%. assuming the population is in hardy-weinberg equilibrium, what percent of the north american population is homozygous dominant for the ability to taste ptc? provide your answer as a number between 0 and 1 to the nearest hundredth.

The ability to taste PTC is thanks to the presence of a minimum of one dominant allele for the PTC taste gene, so a nontaster genotype should be pure recessive(pp). If the frequency of pp is 45%, then the frequency of p would be:

pp=0.45

p= √0.45

p=67%

p+P= 100%

P= 100%- p

P= 100%-67%= 33%

The number of North American population that has is pure dominant(PP) genotype would be:

P=33%

PP= 33%^2= 10.89% = 0.1089 = 0.11

Some people have the ability to taste a bitter chemical called phenylthiocarbamide (PTC).

The shape of the receptor protein determines how strongly it can bind to PTC. Since all people have two copies of every gene, combinations of the bitter taste gene variants determine whether someone finds PTC intensely bitter, somewhat bitter, or without taste at all.

Thus, the ability to taste a bitter chemical called phenylthiocarbamide.

Learn more about phenylthiocarbamide here:

link