When iron reacts with oxygen, it forms iron oxide, or rust. 4 fe + 3 o2 2 fe2o3 if 112 g of iron (fe) combines with 24 g of oxygen (o2), how much iron oxide is formed? a. 24 g fe2o3 b. 136 g fe2o3 c. 112 g fe2o3 d. 88 g fe2o3

The correct answer is option B.

Explanation:

Law of conservation of mass states that' mass can neither be created nor be destroyed. It can only be changed from one form to another'.

This means that in a chemical reaction, sum of the masses of reactants will always be equal to the sum of the masses of products.

As it is given that, 112 grams of iron reacted with 24 grams of oxygen gas as both are the reactants.  

Since, is the product and its mass can be calculated as:

Total mass of reactants = Total mass of products

112 g +24 g = Mass of iron(III) oxide

Mass of iron(III) oxide = 136 g

The correct answer is 136 grams.

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