In a population of turtles, the allele that causes a yellow shell (y) is dominant to the allele that results in a red shell (y). if the dominant allele is present in the population at the 0.72 level and the population is in hardy-weinberg equilibrium, what percentage of the population would be expected to have a red shell? express your answer to the nearest tenth of a percent.

Answer

According to Hardy weinberg principle

P²+2pq+q²=1

where,

p=Y (yellow shell)

q=y (red shell)

Given

Y value = 0.72

Required

y=?

Solution

put value of Y in hardy weinberg equation

(0.72)² + 2q(0.72) + q²= 1

0.51 + 1.44q = 1

1.44q + q² = 1-0.51

1.44q + q² = 0.48

q²= 0.48 / 1.44q

multiply and divide both side by q we will get

q = 0.33

Result 

Thus the value of y allele according to Hardy weinberg equation is 0.33

Were is the question