Defects in computer hard-drives will usually render the entire computer worthless. for a particular model, the percent defective in the past has been 1%. if a sample size of 400 is taken, what would the 95.5% lower control chart limit be?

a. 0.00995
b. 0.09550
c. 0.
d. 0.01000
e. 0.5

E. 0.00005

Explanation:

Here Average Fraction defective, p = 1% = 0.01

95.5% deviation means 2x

x = sqrt{x*(1 - x)/n)}

  = sqrt{0.01*(1 - 0.01)/100}

  = 0.00995

LCL = p - 2x

      = 0.01 - 0.00995

      = 0.00005

Therefore, The 95.5% lower control chart limit be 0.00005

answera public company has access to more capital;

answer: marginal utility of the fourth brownie is 0.

explanation: marginal utility is the addtional utility gained from the consumption of one more unit of a good. it is given by,

so, marginal utility at the 4th unit will be given by

since, the values are not given here, you can simply find marginal utility at fourth unit by subtracting total utility at 3rd unit from total utility at 4th unit.