The diameter of bearingsis known to have a mean of 35 mm with a standard deviation of 0.5 mm. A random sample of 36 bearings is selected. What is the probability that the average diameter of these selected bearings will be between 34.95 and 35.18 mm?

Explanation:

given,

Mean,μ= 35mm  

Standard Deviation,σ = 0.5mm  

Sample size, n = 36  

Sample Standard deviation =

                                             =

                                             = 0.0833

The interested diameter is between 34.95 to 35.18 mm  

Calculating the Z score of the for the diameter mentioned.

now, Form Z-table

Subtracting the value

      = 0.9846 - 0.2741

      = 0.71

Hence, the required probability is that the diameter of bearing is in between  34.95 and 35.18 mm is equal to 0.71.

the investment was $14,174.196

explanation:

a lump sum means that the father of the example made one deposit and leave it be.

we need to know the value of a capital that generated at 4.05% per year during 28 years the sum of $48,613.24

now clearing the formula to solve for capital we got:

and we reach the answer investment = $14,174.20

i would say a penny hope it you