Three heirs (A, B, C) must fairly divide an estate consisting of three items - a house, a car, and a coin collection - using the method of sealed bids. The players' bids (in dollars) are:

I looked for the missing numbers and found the following information:

Heir C wins the house, heir A wins the car and heir B wins the coins.

heir                        A                       B                      C

house              $180,000         $210,000        $220,000

car                     $12,000           $10,000            $8,000

coins                  $3,000            $6,000             $2,000

total                 $195,000         $226,000       $230,000

fair share         $65,000            $75,333          $76,667

Heir A = $65,000 - $12,000 = $53,000. The estate owns heir A $53,000

Heir B = $75,333 - $6,000 = $69,333. The estate owns heir B $69,333.

Heir C = $76,667 - $220,000 = $143,333. Heir C owns $143,333 to the estate.

Surplus = $143,333 - $53,000 - $69,333 = $21,000

Each heir is granted $7,000 as their share form the surplus.

Heir A gets the car and $60,000.

Heir B gets the coins and $76,333

Heir C gets the house and must pay $136,333.

answer; descriptive statistics;