5. Prepare two column cash book from the following transactions for the month of April, 2013
2013
Amt (Rs)
Apr 1 Cash balance
125.000
Apr 2
Paid to Y in full settlement of Rs. 5,000
4.750
Apr 4
Received from Z, allowing him discount of Rs. 100
9,600
Apr 7 Cash purchases
10.000
Apr 11 Cash sales
15.000
Received from X, allowed him discount Rs 500
7500
Paid to W against his dues of Rs. 7,500
7.000
Paid into bank
20.000
Apr 30 Withdrew for personal use
Paid salary and wages
Apr 15
Apr 21
Apr 25
Apr 30

Received from Z, allowing him discount of Rs. 100

9,600

Apr 7 Cash purchases

10.000

Apr 11 Cash sales

15.000

Received from X, allowed him discount Rs 500

7500

Paid to W against his dues of Rs. 7,500

explanation:

a gas is not used in hydraulic machines as the fluid because gas is easily compressible and so if a gas is used, the energy would mostly go into compressing a gas. therefore a liquid is used in hydraulic machines as the fluid.

start by isolating the variable on one side by adding 43w^2 to both sides.   the equation will read:

25w^2+5=0

*subtract 5 from both sides*

25w^2=-5

*divide both sides by 25*

w^2=-1/5

*take the square root of both sides*

w=√(-1/5)

the square root of -1 is i.   the square root of 5 remains √5

the answer is i/√5.

hope this