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Business, 22.06.2019 12:30
Sales at a fast-food restaurant average $6,000 per day. the restaurant decided to introduce an advertising campaign to increase daily sales. to determine the effectiveness of the advertising campaign, a sample of 49 days of sales were taken. they found that the average daily sales were $6,300 per day. from past history, the restaurant knew that its population standard deviation is about $1,000. if the level of significance is 0.01, have sales increased as a result of the advertising campaign? multiple choicea)fail to reject the null hypothesis.b)reject the null hypothesis and conclude the mean is higher than $6,000 per day.c)reject the null hypothesis and conclude the mean is lower than $6,000 per day.d)reject the null hypothesis and conclude that the mean is equal to $6,000 per day.expert answer
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Business, 22.06.2019 16:50
Andrea cujoli is a currency speculator who enjoys "betting" on changes in the foreign currency exchange market. currently the spot price for the japanese yen is Β₯129.87/$ and the 6-month forward rate is Β₯128.53/$. andrea would earn a higher rate of return by buying yen and a forward contract than if she had invested her money in 6-month us treasury securities at an annual rate of 2.50%. true/false?
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Business, 22.06.2019 20:30
The research of robert siegler and eric jenkins on the development of the counting-on strategy is an example of design.
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Business, 22.06.2019 23:00
Customers arrive at rich dunn's styling shop at a rate of 3 per hour, distributed in a poisson fashion. rich can perform an average of 5 haircuts per hour, according to a negative exponential distribution.a) the average number of customers waiting for haircuts= customersb) the average number of customers in the shop= customersc) the average time a customer waits until it is his or her turn= minutesd) the average time a customer spends in the shop= minutese) the percentage of time that rich is busy= percent
Answers: 3
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