Suppose that a task in a project has the following time estimates: to optimistic completion time 11 weeks tm most likely completion time 14 weeks tp pessimistic completion time 23 weeks Compute the expected task variance. The task expected task variance is weeks. (Enter your response rounded to two decimal places.)

6 weeks

Explanation:

Optimistic Completion Time  -  11 weeks

Most likely completion time   -   14 weeks

Pessimistic completion time   -   23 weeks

Compute the expected task variance in weeks. Recall that Variance is a measure of dispersion - a measure that shows the distance or spread between or among values of a variable.

Expected Variance is the average of the variance values.

First,

the variance between optimistic CT and most likely CT is (14 - 11) = 3 weeks

Second,

the variance between pessimistic CT and most likely CT is (23 - 14) = 9 weeks

The expected variance is the average of these two values and that's (3 + 9)/2 = 12/2  = 6 weeks

So the expected variance from the mean completion time of 14 weeks is 6 weeks before or 6 weeks after. This accommodates both the optimist and the pessimist.

i this its 7 years i hope this