Business, 19.03.2021 18:30 EthanIsHyper

Some estimates have been presented to Charlene, the Director of Operations (DO) at Holly Farms, which is considering alternative environmental chambers for a project that will detail laboratory confirmations of online bacteria tests in chicken meat for the presence of E. coli 0157:H7 and Listeria monocytogenes. Chamber D103 Chamber 490G
Installed cost, $ -400,000 -250,000
Annual operating cost, $ per year -4000 -3000
Salvage value at 10% of P, S 40000 25,000
Life, years 3 2

Required:
a. If this project will last for 6 years and i 10% per year, perform an AW method evaluation to determine which chamber is more economical.
b. Chamber D103 can be purchased with different options and, therefore, at different installed costs. They range from$300,000 to $500,000. Will the selection change if one of these other models is installed?

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Answer from: connersitte1221l

Answer is explained in the explanation section below.

Explanation:

Solution:

First, we need to sort out the data given properly, so that we can answer to the best.

Data Given:

For Chamber D103:

Installed Cost = -400,000 USD

Annual Operating Cost Per Year = -4000 USD

Salvage Value 10% of P = 40,000 USD

Life = 3 years

Similarly,

For Chamber 490G:

For Chamber D103:

Installed Cost = -250,000 USD

Annual Operating Cost Per Year = -3000 USD

Salvage Value 10% of P = 25,000 USD

Life = 2 years

For Chamber D103

AW Chamber D103 = -400,000 x (A/P, 10%, 3) + 40000 x (A/F,10%, 3) - 4000

So,

(A/P, 10%, 3) = 0.40211 (from the compound interest table )

(A/F,10%, 3) = 0.30211

AW Chamber D103 = -400,000 x 0.40211 + 40000 x 0.30211 - 4000

AW Chamber D103 = -152,760 USD

For Chamber 490G:

AW Chamber 490G = -250,000 x (A/P,10%,2) + 25000 x (A/F,10%, 2) - 3000

So,

(A/P,10%,2) = 0.5762

(A/F,10%, 2) = 0.4762

AW Chamber 490G = -250,000 x 0.5762 + 25000 x 0.4762 - 3000

AW Chamber 490G = -135,143 USD

So, after evaluating both the chambers using the AW method, more economical is the chamber 490G.

Now, we need to change the values to check whether the chamber selection can be changed or not:

so, New values for Chamber D103

P = -300,000 and Salvage value of 30,000

For Chamber D103

AW Chamber D103 = -300,000 x (A/P, 10%, 3) + 30000 x (A/F,10%, 3) - 4000

So,

(A/P, 10%, 3) = 0.40211 (from the compound interest table )

(A/F,10%, 3) = 0.30211

AW Chamber D103 = -300,000 x 0.40211 + 30,000 x 0.30211 - 4000

AW Chamber D103 = -115,570 USD

New Values for Chamber D103

P = -500,000 and the Salvage Value = 50,000

AW Chamber D103 = -300,000 x (A/P, 10%, 3) + 30000 x (A/F,10%, 3) - 4000

So,

(A/P, 10%, 3) = 0.40211 (from the compound interest table )

(A/F,10%, 3) = 0.30211

AW Chamber D103 = -500,000 x 0.40211 + 50,000 x 0.30211 - 4000

AW Chamber D103 = -189,950 USD

Hence,

At P = 300,000 will definitely change the selection to D103 Chamber.

Answer from: Quest

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Answer from: Quest

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