A loan of $50,000 at 8 percent compounded annually is to be paid off in 25 years by uniform annual payments beginning at the end of the first year. These annual payments proceed on schedule until the end of the eighth year, when the borrower is unable to pay and misses the payment. He negotiates with the lender to increase the remaining 17 payments in such a way that the lender continues to receive 8 percent. What is the amount of the original and final payments in the series?

After all revenue and expense accounts have been closed at the end of the fiscal year, income summary has a debit of $2,450,000 and a credit of $3,000,000. at the same date, retained earnings has a credit balance of $8,222,600, and dividends has a balance of $125,000. required: a. journalize the entries required to complete the closing of the accounts on december 31. refer to the chart of accounts for exact wording of account titles. b. determine the amount of retained earnings at the end of the period.

Kenney co. uses process costing to account for the production of canned energy drinks. direct materials are added at the beginning of the process and conversion costs are incurred uniformly throughout the process. equivalent units have been calculated to be 19,200 units for materials and 16,000 units for conversion costs. beginning inventory consisted of $11,200 in materials and $6,400 in conversion costs. april costs were $57,600 for materials and $64,000 for conversion costs. ending inventory still in process was 6,400 units (100% complete for materials, 50% for conversion). the total cost per unit using the weighted average method would be closest to:

Yowell company granted a sales discount of $360 to a customer when it collected the amount due on account. yowell uses the perpetual inventory system. which of the following answers reflects the effects on the financial statements of only the discount? assets = liab. + equity rev. − exp. = net inc. cash flow a. (360 ) = na + (360 ) (360 ) − na = (360 ) (360 ) oa b. na = (360 ) + 360 360 − na = 360 na c. (360 ) = na + (360 ) (360 ) − na = (360 ) na d. na = (360 ) + 360 360 − na = 360 na