In the nuclear transmutation represented by 168o(p, \alpha) 137n, the emitted particle is in the nuclear transmutation represented by o(p, \alpha) n, the emitted particle is a beta particle. a proton. an alpha particle. a neutron. a positron.

Answer is: an alpha particle.

Nuclear reaction: ¹⁶O + p⁺ → ¹³N + α (alpha particle).
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.
When oxygen-16 gain one proton, atomic mass is 17, but when lose alpha particle atomic mass reduces by four to 13.

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be