The volume of the ideal gas in the container is 9 m3. what would the volume be if four more blocks were placed on top of the lid of the container with the temperature of the gas kept constant? (the lid itself has a mass equal to that of two blocks.) a heated container filled with gas a. 81 m3 b. 18 m3 c. 4.5 m3 d. 3 m3

Answer;
             4.5 m³

Solution:
              The statement says that two blocks are present on a lid of a container with volume of 9 m³. The mass of lid is equal to the mass of two blocks. It means that initially there are four blocks (or four atm pressure) upon 9 m³ volume. 

After that four more blocks are placed on the lid. Means the pressure is increased from 4 atm to 8 atm (2 atm of lid, 2 atm of old blocks, 4 atm of new four blocks).

So, Data generated is,

                  P₁  =  4 atm

                  V₁  =  9 m³

                  P₂  =  8 atm

                  V₂  =  ?

According to Boyle's Law,

                               P₁ V₁  =  P₂ V₂

Solving for V₂,
                               V₂  =  P₁ V₁ / P₂

Putting values,
                               V₂  =  (4 atm × 9 m³) ÷ 8 atm

                               V₂  =  4.5 m³

Solubility would be your answer.