50.0 ml of an hno3 solution were titrated with 36.90 ml of a 0.100 m lioh solution to reach the equivalence point. what is the molarity of the hno3 solution.

0.0738 M

Explanation:

1) Chemical equation:

HNO₃ + LiOH → LiNO₃ + H₂O


2) Mole ratios:

1 mol HNO₃ neutralizes 1 mol LiOH

3) Number of moles of H⁺ from HNO₃:

M = n / V ⇒ n = M × V = 0.050 liter × M

4) Number of moles of OH⁻ from LiOH

M = n / V ⇒ n = M × V = 0.03690 liter × 0,100 M

5) Equivalence point:

number of moles of H⁺ = number of moles of OH⁻

⇒ 0.0500 × M = 0.03690 × 0.100 

⇒ M = 0.03690 × 0.100 / 0.0500 = 0.0738 M

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