Nitrogen gas reacts with hydrogen gas to produce ammonia: ₂ + ₂ → ₃ *not balanced. if 100.0 g of nitrogen gas reacts with 20.0 g of hydrogen gas what mass of ammonia will be produced?

             113.33 g of NH₃

Solution:

The balance chemical equation is as follow,

                                       N₂  +  3 H₂    →    2 NH₃

First find out the limiting reactant;
According to equation,

                     28 g (1 mole) N₂ reacts with  =  6 g (3 mole) of H₂
So,
                             100 g N₂ will react with  =  X g of H₂

Solving for X,
                      X  =  (6 g × 100 g) ÷ 28 g

                      X  =  21.42 g of H₂

So, in order to consume 100 g of N₂ we will require 21.42 g of H₂, but we are provided with only 20 g of H₂, Therefore, H₂ is limiting reagent and will control the yield of product. Hence,
According to equation,

                                 6 g H₂ produced  =  34 g of NH₃
So,
                           20 g H₂ will produce  =  X g of NH₃

Solving for X,
                      X  =  (20 g × 34 g) ÷ 6 g

                      X  =  113.33 g of NH₃