Give the name of the following molecule. a compound with a total of 10 carbons with one double bond and the rest single bonds. there is a chain of eight carbons along the bottom with a double bond between the sixth and seventh carbon when counting from left to right. there is an ethyl group branching off of the third carbon from the left.

           The IUPAC name of compound is 6-Ethyl-2-Octene.

Explanation:

First of all draw a straight chain of 8 carbon atoms.

Make a double bond between carbon number 6 and 7 numbering from left.

Add ethyl group at position 3 starting from left.

The structure sketched is attached below,

According to rules the longest chain containing a double bond is selected. Numbering is started from the end to which double bond is nearer. So, in our case the double bond starts at carbon 2, hence parent name of compound is 2-Octene. Then the substituent at position 6 is named.

The answer is c) pyrite