How many grams of water must be added to 455 grams of potassium sulfate in order to make a 1.50 m solution?

Molar mass of K₂SO₄ = 174.3 g/mol
Mass of K₂SO₄ = 455 g

Moles = mass / molar mass

Hence, moles of K₂SO₄ = 455 g / 174.3 g/mol
                                      = 2.61 mol

Molarity = moles of solute (mol) / Volume of the solution (L)

Hence, volume = moles of solute / molarity
                         = 2.61 mol / 1.50 M
                         = 1.742 L = 1742 mL

Hence, needed volume of water = 1742 mL

Density = mass / volume

Density of water = 0.9972 g/mL

Hence mass of water = 0.9972 g/mL x 1742 mL
                                   = 1737.12 g

Hence, needed mass of water = 1737.12 g.

Firstly, the water in the dams hold gravitational potential energy as they are above ground level. the gravitational potential energy is then transferred to kinetic energy as it falls, spinning the turbinethe turbine then spins the generator, which is a large magnet surrounded by metal coils. by doing this, the generator generates electricity. in this action, the energy transfer taken place is kinetic to electric energy