The haber process for producing ammonia commercially is represented by the equation n2(g) + 3h2(g) -> 2nh3(g). to completely convert 9.0 mol hydrogen gas to ammonia gas, how many moles of nitrogen gas are required?

The number of mole of nitrogen gas, N₂ required for the reaction is 3 moles.

We'll begin obtaining the number of mole of N₂ and H₂ that reacted from the balanced equation.

N₂(g) + 3H₂(g) → 2NH₃(g)

From the balanced equation above,

3 moles of H₂ required 1 mole of N₂.

With the above information in mind, we can obtain the number of mole of N₂ required to react with 9 moles of H₂. This can be obtained as follow:

From the balanced equation above,

3 moles of H₂ required 1 mole of N₂.

Therefore,

9 moles of H₂ will require = 9/3 = 3 moles of N₂.

Thus, 3 moles of N₂ are required for the reaction.

Learn more about stoichiometry:

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