What is the correct balanced equation for the following equilibrium constant expression? co2 (g) two arrows stacked on top of each other. the top arrow points to the right. the bottom arrow points to the left. co (g) + ½ o2 (g) co2 (g) two arrows stacked on top of each other. the top arrow points to the right. the bottom arrow points to the left. co (g) + o2 (g) 2 co2 (g) two arrows stacked on top of each other. the top arrow points to the right. the bottom arrow points to the left. 2 co (g) + o2 (g) 2co (g) + o2 (g) two arrows stacked on top of each other. the top arrow points to the right. the bottom arrow points to the left. co2 (g)

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j