Astudent completes a titration by adding 12.0 milimeters of naoh(aq) of unknown concentration to 16.0 milimeters of 0.15 hcl(aq). what is the molar concentration of the naoh(aq)?

The balanced equation for the above reaction is as follows
NaOH  + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
number of HCl moles reacted - 0.15 mol/L x 0.0160 L = 0.0024 mol
therefore number of NaOH moles reacted - 0.0024 mol
there are 0.0024 mol of NaOH in 12.0 mL
therefore in 1000 L - 0.0024 mol / 12.0 mL x 1000 mL = 0.20 mol
molarity of NaOH is 0.20 M

Dmight be the correct answer

Ido not understand.