If 86.1 g of nitrogen reacts with lithium how many grams of lithium will react

             128 g of Li will react with 86.1 g of N₂ to completely consume it.

Solution:

The balance chemical equation is as follow,

                                      6 Li  +  N₂     →     2 Li₃N

According to this equation,

               28 g (1 mole) N₂ reacts with  =  41.64 g (6 moles) of Li
So,
                  86.1 g of N₂ will react with  =  X g of Li

Solving for X,
                      X  =  (86.1 g × 41.64 g) ÷ 28 g

                      X  =  128 g of Li